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Aeroflot Flight number SU 2408

From Moscow to Rome

Flight information for flight SU 2408

For May 2024

14:30 (GMT +03)
17:20 (GMT +02)

3h 50m
1 hour
3133 km
817 km/h

About Moscow

Sheremetyevo International Airport
SVO
Russia
Find flights to Moscow

About Rome

Leonardo da Vinci–Fiumicino Airport
FCO
Italy
Find flights to Rome

More about Aeroflot flight SU 2408

Flight Sheremetyevo International Airport departs from Moscow Sheremetyevo International Airport at 14:30 and arrives at Rome Leonardo da Vinci–Fiumicino Airport at 17:20.
The flighttime is about 3h 50m. The distance travelled ("as the bird flies"): 3133 Km. So the average speed is roughly 817 Km.
There is an 1 hour time difference between Moscow and Rome